You may define a template member function outside of its class template definition.
When you call a member function of a class template specialization, the compiler will use the template arguments that you used to generate the class template. The following example demonstrates this:
template<class T> class X {
public:
T operator+(T);
};
template<class T> T X<T>::operator+(T arg1) {
return arg1;
};
int main() {
X<char> a;
X<int> b;
a +'z';
b + 4;
}The overloaded addition operator has been defined outside of class X. The statement a + 'z' is equivalent to a.operator+('z'). The statement b + 4 is equivalent to b.operator+(4).
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